u^2-2u+.1=0

Solution for u^2-2u+.1=0 equation:

u^2-2u+.1=0

We add all the numbers together, and all the variables

u^2-2u+0.1=0

a = 1; b = -2; c = +0.1;
Δ = b2-4ac
Δ = -22-4·1·0.1
Δ = 3.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{3.6}}{2*1}=\frac{2-\sqrt{3.6}}{2}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{3.6}}{2*1}=\frac{2+\sqrt{3.6}}{2}
$